Mastering Physics Solutions: Understanding Newton’s Laws
Understanding Newton’s Laws Part A = The net force acting on it is zero. Part B = The net force applied to the block is zero. Part C = It could be moving to the left, moving to the right, or be...
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Mastering Physics Solutions: Pulling Three Blocks
Pulling Three Blocks Part A = 4.50N Part B = 1.50N Solutions Below: Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F....
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Mastering Physics Solutions: Tension in a Massless Rope
Tension in a Massless Rope Part A = T1 Part B = T2 Part C = 3rd Part D = equal to Part E = Fu = Fd Part F = The tension in the rope is everywhere the same. The magnitudes of the forces exerted on the...
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Mastering Physics Solutions: Two Hanging Masses
Two Hanging Masses Part A = M2g Part B = (M1 + M2)g Part C = M2a + M2)g Part D = (M1 + M2)a + (M1 + M2)g Solutions Below: Two blocks with masses M1 and M2 hang one under the other. For this problem,...
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Mastering Physics Solutions: Two Forces Acting at a Point
Two Forces Acting at a Point Part A = -7.96N Part B = 2.34N Part C = 8.29N Part D = 16.4 Degrees Solutions Below: Two forces, F1 and F2, act at a point, as shown in the picture. F1 has a magnitude of...
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Mastering Physics Solutions: Board Pulled Out from under a Box
Board Pulled Out from under a Box Part A = Fmin = μsg(m1 + m2) Solution Below: A small box of mass m1 is sitting on a board of mass m2 and length L . The board rests on a frictionless horizontal...
View ArticleMastering Physics Solutions: Question 4.4
Question 4.4 Part A = All of the preceding Solution Below: Part A If the net force on an object is zero, the object could: Have zero acceleration. Be at rest. Be in motion at a constant velocity. All...
View ArticleMastering Physics Solutions: Question 4.10
Question 4.10 Part A = The magnitude of the force of the brick on the glass is equal to the magnitude of the force of the glass on the brick. Solution Below: Part A A brick hits a glass window. The...
View ArticleMastering Physics Solutions: Question 4.12
Question 4.12 Part A = Only with constant forces. Solution Below: Part A The kinematic equation x = x0 + V0t + 1/2at2 can be used: Only with constant velocities. Only with constant forces. With...
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